12x=x^2-1.6x+6.4

Solution for 12x=x^2-1.6x+6.4 equation:

12x=x^2-1.6x+6.4

We move all terms to the left:

12x-(x^2-1.6x+6.4)=0

We get rid of parentheses

-x^2+12x+1.6x-6.4=0

We add all the numbers together, and all the variables

-1x^2+13.6x-6.4=0

a = -1; b = 13.6; c = -6.4;
Δ = b2-4ac
Δ = 13.62-4·(-1)·(-6.4)
Δ = 159.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13.6)-\sqrt{159.36}}{2*-1}=\frac{-13.6-\sqrt{159.36}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13.6)+\sqrt{159.36}}{2*-1}=\frac{-13.6+\sqrt{159.36}}{-2}
$